a) Ta sẽ bỏ ngoặc rồi nhóm các số hạng hợp lý để thực hiện phép tính:

A = 32,125 – (6,325 + 12,125) – (37 + 13,675)

A = 32,125 – 6,325 – 12,125 – 37 – 13,675

A = 32,125 – 12,125 – 6,325 – 13,675 – 37

A = (32,125 – 12,125) – (6,325 + 13,675) – 37

A = 20 – 20 – 37

A = –37

Vậy A = –37.

b) $B=4,75+{\left(\frac{-1}{2}\right)}^3+0,5^2-3.\frac{-3}{8}$

$B=\frac{475}{100}+\frac{{\left(-1\right)}^3}{2^3}+{\left(\frac{1}{2}\right)}^2-\frac{3.\left(-3\right)}{8}$

$B=\frac{19}{4}+\frac{-1}{8}+\frac{1^2}{2^2}-\frac{-9}{8}$

$B=\frac{19}{4}+\frac{-1}{8}+\frac{1}{4}+\frac{9}{8}$

$B=\left(\frac{19}{4}+\frac{1}{4}\right)+\left(\frac{-1}{8}+\frac{9}{8}\right)$

$B=\frac{20}{4}+\frac{8}{8}$

B = 5 + 1

Vậy B = 6.

c) C = 2021,2345 . 2020,1234 + 2021,2345 . (–2020,1234)

C = 2021,2345 . [2020,1234 + (–2020,1234)]

C = 2021,2345 . 0

C = 0

Vậy C = 0.