Câu hỏi:

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Thực hiện phép tính:

a) (x2y+x3xy2+3)+(x3+xy2xy6)\left( {{x^2}y + {x^3} - x{y^2} + 3} \right) + \left( {{x^3} + x{y^2} - xy - 6} \right).                                                           b) 2x2y2(x3y2x2y312y5)2{x^2}{y^2}\left( {{x^3}{y^2} - {x^2}{y^3} - \frac{1}{2}{y^5}} \right).

c) (3x3x2y+2xy+3)(3x32x2yxy+3)(3{x^3} - {x^2}y + 2xy + 3) - (3{x^3} - 2{x^2}y - xy + 3).         d) [(3ab)29a2b4]:(8ab2)\left[ {{{\left( {3ab} \right)}^2} - 9{a^2}{b^4}} \right]:\left( {8a{b^2}} \right).

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Lời giải

Hướng dẫn giải:

a) (x2y+x3xy2+3)+(x3+xy2xy6)\left( {{x^2}y + {x^3} - x{y^2} + 3} \right) + \left( {{x^3} + x{y^2} - xy - 6} \right)

=x2y+x3xy2+3+x3+xy2xy6 = {x^2}y + {x^3} - x{y^2} + 3 + {x^3} + x{y^2} - xy - 6

=(x3+x3)+(xy2+xy2)+x2yxy+(36) = \left( {{x^3} + {x^3}} \right) + \left( { - x{y^2} + x{y^2}} \right) + {x^2}y - xy + (3 - 6)

=2x3+x2yxy3 = 2{x^3} + {x^2}y - xy - 3.

b) 2x2y2(x3y2x2y312y5)2{x^2}{y^2}\left( {{x^3}{y^2} - {x^2}{y^3} - \frac{1}{2}{y^5}} \right)

=2x2y2.x3y2+2x2y2.(x2y3)+2x2y2.(12y5) = 2{x^2}{y^2}\,.\,{x^3}{y^2} + 2{x^2}{y^2}\,.\,\left( { - {x^2}{y^3}} \right) + 2{x^2}{y^2}.\left( {\frac{{ - 1}}{2}{y^5}} \right)

=2x5y42x4y5x2y7 = 2{x^5}{y^4} - 2{x^4}{y^5} - {x^2}{y^7}.

c) (3x3x2y+2xy+3)(3x32x2yxy+3)\left( {3{x^3} - {x^2}y + 2xy + 3} \right) - \left( {3{x^3} - 2{x^2}y - xy + 3} \right)

=3x3x2y+2xy+33x3+2x2y+xy3 = 3{x^3} - {x^2}y + 2xy + 3 - 3{x^3} + 2{x^2}y + xy - 3

=(3x33x3)+(x2y+2x2y)+(2xy+xy)+(33) = \left( {3{x^3} - 3{x^3}} \right) + \left( { - {x^2}y + 2{x^2}y} \right) + \left( {2xy + xy} \right) + (3 - 3)

=x2y+3xy = {x^2}y + 3xy.

d) P=[(3ab)29a2b4]:(8ab2)P = \left[ {{{\left( {3ab} \right)}^2} - 9{a^2}{b^4}} \right]:\left( {8a{b^2}} \right)

=(9a2b29a2b4):(8ab2)=98a98ab2 = \left( {9{a^2}{b^2} - 9{a^2}{b^4}} \right):\left( {8a{b^2}} \right) = \frac{9}{8}a - \frac{9}{8}a{b^2}.

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