Câu hỏi:

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Thực hiện phép tính:

a) (3xyz3x2+5xy1)(5x2+xyz5xy+3y)\left( {3xyz - 3{x^2} + 5xy - 1} \right) - \left( {5{x^2} + xyz - 5xy + 3 - y} \right);

b) (3x3x2y+2xy+3)+(x2y2xy2)\left( {3{x^3} - {x^2}y + 2xy + 3} \right) + \left( {{x^2}y - 2xy - 2} \right);

c) (2xy34y8x)(12y)\left( {2x{y^3} - 4y - 8x} \right) \cdot \left( {\frac{1}{2}y} \right);

d) (x8y8+2x5y5+7x3y3):(x2y2)\left( {{x^8}{y^8} + 2{x^5}{y^5} + 7{x^3}{y^3}} \right):\left( { - {x^2}{y^2}} \right).

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Lời giải

Hướng dẫn giải:

a) (3xyz3x2+5xy1)(5x2+xyz5xy+3y)\left( {3xyz - 3{x^2} + 5xy - 1} \right) - \left( {5{x^2} + xyz - 5xy + 3 - y} \right)                                                                

=3xyz3x2+5xy15x2xyz+5xy3+y = 3xyz - 3{x^2} + 5xy - 1 - 5{x^2} - xyz + 5xy - 3 + y

=(3xyzxyz)+(3x25x2)+(5xy+5xy)+y+(13) = \left( {3xyz - xyz} \right) + \left( { - 3{x^2} - 5{x^2}} \right) + \left( {5xy + 5xy} \right) + y + \left( { - 1 - 3} \right)

=2xyz8x2+10xy+y4 = 2xyz - 8{x^2} + 10xy + y - 4.

b) (3x3x2y+2xy+3)+(x2y2xy2)\left( {3{x^3} - {x^2}y + 2xy + 3} \right) + \left( {{x^2}y - 2xy - 2} \right)

=3x3x2y+2xy+3+x2y2xy2 = 3{x^3} - {x^2}y + 2xy + 3 + {x^2}y - 2xy - 2

=(x2y+x2y)+(2xy2xy)+3x3+(32) = \left( { - {x^2}y + {x^2}y} \right) + \left( {2xy - 2xy} \right) + 3{x^3} + \left( {3 - 2} \right)

=3x3+1 = 3{x^3} + 1.

c) (2xy34y8x)(12y)\left( {2x{y^3} - 4y - 8x} \right) \cdot \left( {\frac{1}{2}y} \right)

=2xy3.(12y)+(4y).(12y)+(8x).(12y) = 2x{y^3}.\left( {\frac{1}{2}y} \right) + \left( { - 4y} \right).\left( {\frac{1}{2}y} \right) + \left( { - 8x} \right).\left( {\frac{1}{2}y} \right)

=xy42y24xy = x{y^4} - 2{y^2} - 4xy.

d) (x8y8+2x5y5+7x3y3):(x2y2)\left( {{x^8}{y^8} + 2{x^5}{y^5} + 7{x^3}{y^3}} \right):\left( { - {x^2}{y^2}} \right).

=x8y8:(x2y2)+2x5y5:(x2y2)+7x3y3:(x2y2) = {x^8}{y^8}:\left( { - {x^2}{y^2}} \right) + 2{x^5}{y^5}:\left( { - {x^2}{y^2}} \right) + 7{x^3}{y^3}:\left( { - {x^2}{y^2}} \right)

= x6y62x3y37xy =  - {x^6}{y^6} - 2{x^3}{y^3} - 7xy.

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