Lý thuyết Công thức lượng giác (Kết nối tri thức 2024) Toán 11

Tóm tắt lý thuyết Toán 11 Bài 2: Công thức lượng giác ngắn gọn, chính xác sách Kết nối tri thức sẽ giúp học sinh nắm vững kiến thức trọng tâm, ôn luyện để học tốt Toán 11.

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Lý thuyết Toán lớp 11 Bài 2: Công thức lượng giác

A. Lý thuyết Công thức lượng giác

1. Công thức cộng

Unknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span

2. Công thức nhân đôi

sin2a=2sinacosacos2a=cos2asin2a=2cos2a1=12sin2atan2a=2tana1tan2asin2a=2sinacosacos2a=cos2asin2a=2cos2a1=12sin2atan2a=2tana1tan2a

Suy ra, công thức hạ bậc:

sin2a=1cos2a2,cos2a=1+cos2a2sin2a=1cos2a2,cos2a=1+cos2a2

Unknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span3. Công thức biến đổi tích thành tổng

cosacosb=12[cos(a+b)+cos(ab)]sinasinb=12[cos(ab)cos(a+b)]sinacosb=12[sin(a+b)+sin(ab)]Unknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span

4. Công thức biến đổi tổng thành tích

cosa+cosb=2cosa+b2cosab2cosacosb=2sina+b2sinab2sina+sinb=2sina+b2cosab2sinasinb=2cosa+b2sinab2Unknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span

Lý thuyết Công thức lượng giác (Kết nối tri thức 2023) hay, chi tiết | Toán lớp 11 (ảnh 1)

B. Bài tập Công thức lượng giác

Bài 1. Tính sin2a và tan2a biết cos a = Unknown node type: spanUnknown node type: span  Unknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span.

Hướng dẫn giải

 Unknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spannên sina < 0.

Ta có:

sin2a + cos2a = 1 ⇒ sin2a = 1 – cos2a = 1 - Lý thuyết Toán 11 Kết nối tri thức Bài 2: Công thức lượng giác = Unknown node type: spanUnknown node type: span

⇒ sina = Unknown node type: spanUnknown node type: spanUnknown node type: span.

Ta có: sin2a = 2sina cosa = 2.Lý thuyết Toán 11 Kết nối tri thức Bài 2: Công thức lượng giác.Unknown node type: spanUnknown node type: span = Unknown node type: spanUnknown node type: spanUnknown node type: span

Ta có: tana = Unknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span

Unknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span=Lý thuyết Toán 11 Kết nối tri thức Bài 2: Công thức lượng giác=Unknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span.

Bài 2. Tính

a) sinLý thuyết Toán 11 Kết nối tri thức Bài 2: Công thức lượng giác biết sin a = Unknown node type: spanUnknown node type: span và 0 < a < Unknown node type: spanUnknown node type: span;

b) cosUnknown node type: spanUnknown node type: spanUnknown node type: span.cosUnknown node type: spanUnknown node type: span + sinUnknown node type: spanUnknown node type: spanUnknown node type: span.sinUnknown node type: spanUnknown node type: span.

Hướng dẫn giải

a) Vì 0Unknown node type: spanUnknown node type: span nên cosa > 0.

Ta có: sin2a + cos2a = 1 ⇒ cos2a = 1 – sin2a = 1-Lý thuyết Toán 11 Kết nối tri thức Bài 2: Công thức lượng giác=Unknown node type: spanUnknown node type: span

⇒ cosa = null.

Vậy sinLý thuyết Toán 11 Kết nối tri thức Bài 2: Công thức lượng giácUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span .

Lý thuyết Toán 11 Kết nối tri thức Bài 2: Công thức lượng giác

Suy ra: Unknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span.

Bài 3. Tính

a) cos(–15°) + cos255°;

b) sinUnknown node type: spanUnknown node type: spanUnknown node type: spansinUnknown node type: spanUnknown node type: spanUnknown node type: span.

Hướng dẫn giải

a) Ta có:

cos(-15o) + cos255o = 2.cosUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span.cosUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span

= 2.cos120o.cos(135o) = 2Lý thuyết Toán 11 Kết nối tri thức Bài 2: Công thức lượng giác

Vậy cos(–15°) + cos255° = Unknown node type: spanUnknown node type: span.

b) Ta có:

Lý thuyết Toán 11 Kết nối tri thức Bài 2: Công thức lượng giác

Vậy Unknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: spanUnknown node type: span.

Video bài giảng Toán 11 Bài 2: Công thức lượng giác - Kết nối tri thức

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